
E6581301
A-23
1
■ Calorific values of the inverter and the required ventilation
The energy loss when the inverter converts power from AC to DC and then back to AC is about 5%. In order to
suppress the rise in temperature inside the cabinet when this loss becomes heat loss, the interior of the cabinet must
be ventilated and cooled.
The amount of forced air-cooling ventilation required and the necessary heat exchange surface area when operating in
a sealed cabinet according to motor capacity are as follows.
Volta
e
class
Applicable Moto
(kW)
Calorific values
(W)
Amount of forced air coolin
ventilation required
(m
3
/min)
Heat exchange surface area
required for sealed storage
cabinet
(m
2
)
0.4 50 0.29 1.0
0.75 70 0.40 1.4
1.5 113 0.65 2.3
2.2 135 0.78 2.7
3.7/4.0 191 0.92 3.2
5.5 307 1.8 6.2
7.5 408 2.4 8.2
11 593 3.4 11.9
15 692 4.0 13.9
18.5 800 4.6 16.0
22 865 5.0 17.3
30 1140 6.6 22.8
37 1340 7.7 26.8
45 1570 9.0 31.4
55 1720 9.9 34.4
200V
75 2210 12.7 44.2
0.75 57 0.33 1.2
1.5 82 0.47 1.7
2.2 112 0.64 2.3
3.7/4.0 136 0.78 2.8
5.5 262 1.5 5.3
7.5 328 1.9 6.6
11 448 2.6 9.0
15 577 3.3 11.6
18.5 682 3.9 13.7
22 720 4.2 14.4
30 980 5.6 19.6
37 1180 6.8 23.6
45 1360 7.8 27.2
55 1560 9.0 31.2
75 2330 13.4 46.6
90 2410 13.8 48.2
110 2730 15.6 54.6
132 3200 18.3 64.0
160 3820 21.9 76.4
200 4930 28.2 98.6
220 5405 30.9 108.1
280 6830 39.1 136.6
355
400
400V
500
Note1: The heat loss for the optional external devices (input reactor, DC reactor, radio noise reduction filters, etc.) is
not included in the calorific values in the table.
Note2: Each calorific value in the table refers to the quantity of heat that an inverter produces when it is operated
continuously at the factory default EH (carrier frequency) under a load factor of 100%.
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